Differential Equation: $y' = x^3 - 2xy$, where $y(1)=1$ and $y' = 2(2x-y)$ that passes through (0,1)

Can anyone solve this D. E.?

y' = x^3 - 2xy, where y(1)=1


y' = 2(2x-y) that passes through (0,1)

Jhun Vert's picture

Both equations are linear differential equation of order one. Try this: https://mathalino.com/node/495

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