# Differential Equation: $y' = x^3 - 2xy$, where $y(1)=1$ and $y' = 2(2x-y)$ that passes through (0,1)

Can anyone solve this D. E.?
y' = x^3 - 2xy, where y(1)=1
and
y' = 2(2x-y) that passes through (0,1)

- Log in to post comments

Can anyone solve this D. E.?
y' = x^3 - 2xy, where y(1)=1
and
y' = 2(2x-y) that passes through (0,1)

- Log in to post comments

All trademarks and copyrights on this page are owned by their respective owners. Forum posts are owned by the individual posters.

## Both equations are linear

Both equations are linear differential equation of order one. Try this: https://mathalino.com/node/495