Differential Equation: $y' = x^3 - 2xy$, where $y(1)=1$ and $y' = 2(2x-y)$ that passes through (0,1)

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December 5, 2020 - 5:09pm
#1
The Organist
Differential Equation: $y' = x^3 - 2xy$, where $y(1)=1$ and $y' = 2(2x-y)$ that passes through (0,1)

Can anyone solve this D. E.?

y' = x^3 - 2xy, where y(1)=1

and

y' = 2(2x-y) that passes through (0,1)

Tags: 
Calculus
DE
Integration
Math
Differential Equation, DE
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December 7, 2020 - 4:16pm
Jhun Vert
Jhun Vert's picture

Both equations are linear differential equation of order one. Try this: https://mathalino.com/node/495

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