Differential Equation, DE

Differential Equation: y' = x^3 - 2xy, where y(1)=1 and y' = 2(2x-y) that passes through (0,1)

Can anyone solve this D. E.?

y' = x^3 - 2xy, where y(1)=1

and

y' = 2(2x-y) that passes through (0,1)

Arbitrary constant

y=x^2+C1e^2x+C2e^3x

Thank you again

Families of Curves: family of circles with center on the line y= -x and passing through the origin

Find the diff equation of family of circles with center on the line y= -x and passing through the origin.

THANK YOU :)

Sydney Sales's picture

DE: (x²+4) y' + 3 xy = x

(x²+4) y' + 3 xy = x

 
 
Subscribe to RSS - Differential Equation, DE