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Differential Equation: $y' = x^3 - 2xy$, where $y(1)=1$ and $y' = 2(2x-y)$ that passes through (0,1)

Submitted by The Organist on Sat, 12/05/2020 - 17:09

Can anyone solve this D. E.?

y' = x^3 - 2xy, where y(1)=1

and

y' = 2(2x-y) that passes through (0,1)

  • Read more about Differential Equation: $y' = x^3 - 2xy$, where $y(1)=1$ and $y' = 2(2x-y)$ that passes through (0,1)
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