## Differential Equation: $y' = x^3 - 2xy$, where $y(1)=1$ and $y' = 2(2x-y)$ that passes through (0,1)

Can anyone solve this D. E.?
y' = x^3 - 2xy, where y(1)=1
and
y' = 2(2x-y) that passes through (0,1)

Can anyone solve this D. E.?
y' = x^3 - 2xy, where y(1)=1
and
y' = 2(2x-y) that passes through (0,1)