Differential Equation: $y' = x^3 - 2xy$, where $y(1)=1$ and $y' = 2(2x-y)$ that passes through (0,1) Submitted by The Organist on Sat, 12/05/2020 - 17:09 Can anyone solve this D. E.? y' = x^3 - 2xy, where y(1)=1 and y' = 2(2x-y) that passes through (0,1) Read more about Differential Equation: $y' = x^3 - 2xy$, where $y(1)=1$ and $y' = 2(2x-y)$ that passes through (0,1)1 commentLog in or register to post comments
