Differential Equation: $y' = x^3 - 2xy$, where $y(1)=1$ and $y' = 2(2x-y)$ that passes through (0,1)
Can anyone solve this D. E.?
y' = x^3 - 2xy, where y(1)=1
and
y' = 2(2x-y) that passes through (0,1)
Integration
Integral Calculus: $\displaystyle \int \csc^3 x \, \cos^3 x dx$
Integral of csc^3 cos^3 xdx
Integration by Substitution
Kinda need some help.
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Integral Calculus: $\displaystyle \int \ln \left[ x+(1-x)^{1/2} \right] dx$
Pa help po sana dito sa question na to.
(integral of) ln (x+(1-x)^(1/2))dx
check my solution: $\displaystyle \int \dfrac{(6x^2 - 3x + 1) dx}{(4x + 1)(x^2 + 1)}$
hey...can anyone here check my solution to the problem??not sure whether I got it correctly and do not want to pay https://www.chegg.com/ or http://yourhomeworkhelp.org for the thing I practically did myself
thanks
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Please help me answer
∫dx/cos(x)sin(x)
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