ask ko lang po kung panong gagawin ko sa equation na to: integration of Submitted by CHo Cruz on Sun, 08/16/2015 - 21:16 (3-x)dx/ (x^2-6x-9)^5/2 Tags Integration Power Formula Log in to post comments Re: ask ko lang po kung panong gagawin ko sa equation na to:... Jhun Vert Thu, 08/20/2015 - 06:45 You can use power formula: $\displaystyle \int \dfrac{(3 - x) \, dx}{(x^2 - 6x - 9)^{5/2}}$ $= \displaystyle \int (x^2 - 6x - 9)^{-5/2} \, (3 - x) \, dx$ $= \displaystyle -\dfrac{1}{2} \int (x^2 - 6x - 9)^{-5/2} \, [ \, -2(3 - x) \, ] \, dx$ $= \displaystyle -\dfrac{1}{2} \int (x^2 - 6x - 9)^{-5/2} \, (2x - 6) \, dx$ Log in to post comments
Re: ask ko lang po kung panong gagawin ko sa equation na to:... Jhun Vert Thu, 08/20/2015 - 06:45 You can use power formula: $\displaystyle \int \dfrac{(3 - x) \, dx}{(x^2 - 6x - 9)^{5/2}}$ $= \displaystyle \int (x^2 - 6x - 9)^{-5/2} \, (3 - x) \, dx$ $= \displaystyle -\dfrac{1}{2} \int (x^2 - 6x - 9)^{-5/2} \, [ \, -2(3 - x) \, ] \, dx$ $= \displaystyle -\dfrac{1}{2} \int (x^2 - 6x - 9)^{-5/2} \, (2x - 6) \, dx$ Log in to post comments
Re: ask ko lang po kung panong gagawin ko sa equation na to:...
You can use power formula:
$\displaystyle \int \dfrac{(3 - x) \, dx}{(x^2 - 6x - 9)^{5/2}}$
$= \displaystyle \int (x^2 - 6x - 9)^{-5/2} \, (3 - x) \, dx$
$= \displaystyle -\dfrac{1}{2} \int (x^2 - 6x - 9)^{-5/2} \, [ \, -2(3 - x) \, ] \, dx$
$= \displaystyle -\dfrac{1}{2} \int (x^2 - 6x - 9)^{-5/2} \, (2x - 6) \, dx$