Member for 9 years 11 months By Sakura_sama, 1 May, 2016 Please help me answer ∫dx/cos(x)sin(x) Tags Integration Trigonometric Function Member for 17 years 6 months $\displaystyle \int \dfrac{dx $\displaystyle \int \dfrac{dx}{\cos x \, \sin x} = 2\int \dfrac{dx}{2\cos x \, \sin x}$ $= 2\displaystyle \int \dfrac{dx}{\sin 2x}$ $= 2\displaystyle \int \csc 2x \, dx$ $= \displaystyle \int \csc 2x \, (2 \, dx)$ $= \ln (\csc 2x - \cot 2x) + C$ answer Log in or register to post comments
Member for 17 years 6 months $\displaystyle \int \dfrac{dx $\displaystyle \int \dfrac{dx}{\cos x \, \sin x} = 2\int \dfrac{dx}{2\cos x \, \sin x}$ $= 2\displaystyle \int \dfrac{dx}{\sin 2x}$ $= 2\displaystyle \int \csc 2x \, dx$ $= \displaystyle \int \csc 2x \, (2 \, dx)$ $= \ln (\csc 2x - \cot 2x) + C$ answer
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17 years 6 months$\displaystyle \int \dfrac{dx
$\displaystyle \int \dfrac{dx}{\cos x \, \sin x} = 2\int \dfrac{dx}{2\cos x \, \sin x}$
$= 2\displaystyle \int \dfrac{dx}{\sin 2x}$
$= 2\displaystyle \int \csc 2x \, dx$
$= \displaystyle \int \csc 2x \, (2 \, dx)$
$= \ln (\csc 2x - \cot 2x) + C$ answer