Discussion on: Solution to Problem 411 | Shear and Moment Diagrams

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In reply to by Kim Michael So…

The erroneous line has been updated... thanks
$F_1 = \frac{1}{2}x(w_o - y)$

$F_1 = \dfrac{1}{2}x \, \left[ w_o - \dfrac{w_o}{L}(L - x) \right]$

$F_1 = \dfrac{1}{2}x \, \left[ w_o - w_oL - \dfrac{w_o}{L}x \right]$   ←   wrong line

$F_1 = \dfrac{w_o}{2L}x^2$
 

Correction:
$F_1 = \dfrac{1}{2}x \, \left[ w_o - w_o + \dfrac{w_o}{L}x \right]$
 

Status: updated