$T_1 = \frac{1}{4}BC = \frac{1}{4}(122.4) = 30.6 ~ \text{m}$
$T_2 = 122.4 - 30.6 = 91.8 ~ \text{m}$
$R_1 = \dfrac{T_1}{\tan 14^\circ} = \dfrac{30.6}{\tan 14^\circ} = 122.73 ~ \text{m}$ ← [ A ] answer for part 1
$R_2 = \dfrac{T_2}{\tan 30^\circ} = \dfrac{91.8}{\tan 30^\circ} = 159.00 ~ \text{m}$
Total length of road from A to D
$L = 154.40 + \dfrac{2\pi(122.73)(28^\circ)}{180^\circ} + \dfrac{\pi(159)(60^\circ)}{180^\circ} + 193.20$
$L = 154.40 + 59.98 + 166.50 + 193.20$
$L = 574.08 ~ \text{m}$ ← [ C ] answer for part 2
Area of road pavement
$\begin{align}
A = & 154.40(6.10) + \dfrac{\pi \left[ (119.68 + 6.10)^2 - 119.68^2 \right](28^\circ)}{360^\circ} \\
& + \dfrac{\pi \left[ (155.95 + 6.10)^2 - 155.95^2 \right](60^\circ)}{360^\circ} + 193.20(6.10)
\end{align}$
$A = 160.50 + 365.86 + 1015.68 + 1178.52$
$A = 2720.56 ~ \text{m}^2$
Cost of concrete pavement
$C = 1,800(2720.56) = \text{P}4,897,008$ ← [ D ] answer for part 3
Comments
Bakit po inadd yong 154.40 at
Bakit po inadd yong 154.40 at 6.10
Wala akong nakita sa solution
Wala akong nakita sa solution na inadd yang dalawa. Do you mean minultiply? If yes, rectangular kasi ang shape sa protion na yan kaya minultiply para makuha ang area.
saan po galing yung 154.40
saan po galing yung 154.40
AB - T1.
AB - T1.
yung nakuha mong 30.6 i minus
yung nakuha mong 30.6 i minus mo sa 185
yup I noticed that too.
yup I noticed that too. siguro nagkamali lang sa solution. tayo nalang po mag adjust hehe
Nakita ko na... doon pala sa
Nakita ko na... doon pala sa next line, na add pala talaga... yeah kayo na mag adjust... di ko na i-edit... hahaha
san nakuha 28 degree
san nakuha 28 degree
The azimuths are reckoned
The azimuths are reckoned from South.
Paano po nakuha yung 119.68,
Paano po nakuha yung 119.68, 155.95? Salamat po.
Hi! bakit po 60 yung sa v2?
Hi! bakit po 60 yung sa v2? diba dapat po 62?