$T_1 = \frac{1}{4}BC = \frac{1}{4}(122.4) = 30.6 ~ \text{m}$

$T_2 = 122.4 - 30.6 = 91.8 ~ \text{m}$

$R_1 = \dfrac{T_1}{\tan 14^\circ} = \dfrac{30.6}{\tan 14^\circ} = 122.73 ~ \text{m}$ ← [ A ] *answer for part 1*

$R_2 = \dfrac{T_2}{\tan 30^\circ} = \dfrac{91.8}{\tan 30^\circ} = 159.00 ~ \text{m}$

Total length of road from *A* to *D*

$L = 154.40 + \dfrac{2\pi(122.73)(28^\circ)}{180^\circ} + \dfrac{\pi(159)(60^\circ)}{180^\circ} + 193.20$

$L = 154.40 + 59.98 + 166.50 + 193.20$

$L = 574.08 ~ \text{m}$ ← [ C ] *answer for part 2*

Area of road pavement

$\begin{align}

A = & 154.40(6.10) + \dfrac{\pi \left[ (119.68 + 6.10)^2 - 119.68^2 \right](28^\circ)}{360^\circ} \\

& + \dfrac{\pi \left[ (155.95 + 6.10)^2 - 155.95^2 \right](60^\circ)}{360^\circ} + 193.20(6.10)

\end{align}$

$A = 160.50 + 365.86 + 1015.68 + 1178.52$

$A = 2720.56 ~ \text{m}^2$

Cost of concrete pavement

$C = 1,800(2720.56) = \text{P}4,897,008$ ← [ D ] *answer for part 3*

## Bakit po inadd yong 154.40 at

Bakit po inadd yong 154.40 at 6.10

## Wala akong nakita sa solution

In reply to Bakit po inadd yong 154.40 at by Anonymous (not verified)

Wala akong nakita sa solution na inadd yang dalawa. Do you mean minultiply? If yes, rectangular kasi ang shape sa protion na yan kaya minultiply para makuha ang area.

## saan po galing yung 154.40

In reply to Wala akong nakita sa solution by Jhun Vert

saan po galing yung 154.40

## AB - T1.

In reply to saan po galing yung 154.40 by anon (not verified)

AB-T_{1}.## yung nakuha mong 30.6 i minus

In reply to saan po galing yung 154.40 by anon (not verified)

yung nakuha mong 30.6 i minus mo sa 185

## yup I noticed that too.

In reply to Bakit po inadd yong 154.40 at by Anonymous (not verified)

yup I noticed that too. siguro nagkamali lang sa solution. tayo nalang po mag adjust hehe

## Nakita ko na... doon pala sa

In reply to yup I noticed that too. by anonymous (not verified)

Nakita ko na... doon pala sa next line, na add pala talaga... yeah kayo na mag adjust... di ko na i-edit... hahaha

## san nakuha 28 degree

In reply to Bakit po inadd yong 154.40 at by Anonymous (not verified)

san nakuha 28 degree

## The azimuths are reckoned

In reply to san nakuha 28 degree by Anonymous (not verified)

The azimuths are reckoned from South.

## Pwede po pa-explain pano

In reply to The azimuths are reckoned by Jhun Vert

Pwede po pa-explain pano naging 28°

## Paano po nakuha yung 119.68,

Paano po nakuha yung 119.68, 155.95? Salamat po.

## I know late na po itong reply

In reply to Paano po nakuha yung 119.68, by Cestudent (not verified)

I know late na po itong reply ko, pero sasagutin ko parin para dun sa mga makakakita nito in the future tas may gantong tanong din. Ima-minus niyo po yung width ng pavement sa radius na nakuha mo kaya naging ganan po ang sagoot

## Hi! bakit po 60 yung sa v2?

Hi! bakit po 60 yung sa v2? diba dapat po 62?

## kaya po 60 gawa ng yung

In reply to Hi! bakit po 60 yung sa v2? by Anonymous (not verified)

kaya po 60 gawa ng yung equivalent na bearing ng azimuth na 302 is 58 and then imaminus mo siya sa 90 tas ang makukuha mo dun is ipaplus mo sa 28 which is yung bearing nung sa azimuth na 242. Yun po sana na gets