01 Area of a right triangle of known median bisecting the hypotenuse

By Pythagorean Theorem:

Area of the triangle
$A = \frac{1}{2}(3x) \sin 60^\circ + \frac{1}{2}(3x) \sin 120^\circ$

$A = \frac{1}{2}(3)(3) \sin 60^\circ + \frac{1}{2}(3)(3) \sin 120^\circ$

$A = 7.79 ~ \text{cm}^2$   ←   answer