$V = \pi {\displaystyle {\int_{x_1}}^{x_2}} {y_U}^2 \, dx$
$V = \pi {\displaystyle {\int_0}^2} (x^{1/2})^2 \, dx$
$V = \pi {\displaystyle {\int_0}^2} x \, dx$
$V = \pi \left[ \dfrac{x^2}{2} \right]_0^2$
$V = \frac{1}{2}\pi [ \, 2^2 - 0^2 \, ]$
$V = 2\pi \, \text{ unit}^3$ answer