Problem 335 | Equilibrium of Parallel Force System

Replace the 3-20 kN forces and 2-10 kN forces by a single 80 kN force
$\Sigma M_B = 0$

$15R_A = 10(60) + 7.5(80) + 5(50)$

$R_A = 96.67 \, \text{ kN}$           answer
 

 

$\Sigma M_A = 0$

$15R_B = 5(60) + 7.5(80) + 10(50)$

$R_B = 93.33 \, \text{ kN}$           answer