$ye^{2x} \, dx = (4 + e^{2x}) \, dy$
$\dfrac{ye^{2x} \, dx}{y(4 + e^{2x})} = \dfrac{(4 + e^{2x}) \, dy}{y(4 + e^{2x})}$
$\dfrac{e^{2x} \, dx}{4 + e^{2x}} = \dfrac{dy}{y}$
$\displaystyle \dfrac{1}{2} \int \dfrac{e^{2x} (2 \, dx)}{4 + e^{2x}} = \int \dfrac{dy}{y}$
$\frac{1}{2} \ln (4 + e^{2x}) = \ln y + \ln c$
$\frac{1}{2} \ln (4 + e^{2x}) = \ln cy$
$\ln (4 + e^{2x}) = 2\ln cy$
$\ln (4 + e^{2x}) = \ln (cy)^2$
$\ln (4 + e^{2x}) = \ln c^2y^2$
$4 + e^{2x} = c^2y^2$
$c^2y^2 = 4 + e^{2x}$ answer