Problem 01 Water is flowing into a vertical cylindrical tank at the rate of 24 ft3/min. If the radius of the tank is 4 ft, how fast is the surface rising?
Solution 01
$\dfrac{dV}{dt} = 16\pi \dfrac{dh}{dt}$
$24 = 16\pi \dfrac{dh}{dt}$
$\dfrac{dh}{dt} = 0.477 \,\, \text{ ft/min }$ answer
Problem 02 Water flows into a vertical cylindrical tank at 12 ft3/min, the surface rises 6 in/min. Find the radius of the tank.
Solution 02
$\dfrac{dV}{dt} = \pi r^2 \dfrac{dh}{dt}$
$12 = \pi r^2 (0.5)$
$r = \sqrt{\dfrac{12}{0.5\pi}\,} = 2.76 \,\, \text{ ft }$ answer
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