Time When The Angle Between The Hands Of The Clock Were Bisected By The 3 O'clock Mark

$10 + \dfrac{x}{12} + \theta = 15$

$\theta = 5 - \dfrac{x}{12}$
 

 

$x = 15 + \theta$

$x = 15 + \left( 5 - \dfrac{x}{12} \right)$

$x = 20 - \dfrac{x}{12}$

$\dfrac{13x}{12} = 20$

$x = 18.46 \, \text{ min}$

$x = 18 \text{ min and } 27.6 \text{ sec}$
 

$\text{Time} = 2:18:27.6$           answer - A
 

Preferred Solution

 

 

$\theta = \theta$

$x - 15 = 5 - \dfrac{x}{12}$

$x = 18.46 \, \text{ min}$