Steel design
Is there a limit of value of modular ratio? If there is, what is the limit?
- Read more about Steel design
- Log in or register to post comments
Is there a limit of value of modular ratio? If there is, what is the limit?
What is the answer to the question If 5n+6 is odd then n is odd
using the contraposition/contrapositive.
a force of a baseball swing. a baseball ha mass 0.145 kg
a. if the velocity of a pitched ball has a magnitude of 45.0 m/s and the batted ball's velocity is 55 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bait.
b. if the ball remains in contact with the bat for 2 m/s, find the magnitude of the average force applied by bat.
A spherical container of negligible thickness holding a hot fluid at 1400
and having
an outer diameter of 0.4 m is insulated with three layers of each 50 mm thick
insulation of k1 = 0.02: k2 = 0.06 and k3 = 0.16 W/mK. (Starting from inside). The
outside surface temperature is 300C. Determine (i) the heat loss, and (ii) Interface
temperatures of insulating layers.
need explaination plss..
[(1-xy)^-2]dx + [y^2-x^2(1-xy)^-2]dy=0 ;when x=1, y=1
The radial stress p at distance r for the axis of the thick cylinder subjected to internal pressure is given by p + r (dp/dr) = A − p where A is a constant. If p = p0 at the inner wall r = r1 and is negligible (p = 0) at the outer wall r = r2 find an expression for p.
A 400N weight starts down a 300 incline with an initial velocity of 4m/s. What is the velocity of the weight after 10 seconds if F=0.20 for the incline?
A steel ring of outer diameter 300mm and internal diameter of 200mm is shrunked unto a solid steel shaft , the interference is arranged such that the radial pressure between the meeting surfaces will not fall bellow 300MN/m^2 while the assembly rotates in circles. If the maximum circumferencial stress on the inside of d surface of the ring is limited to 240MN/m^2. Determine the maximum speed at which the assembly can be rotated . Assuming that no relative slip occur between the shaft and the ring.
Please hep me to obtain the general solution
xdy-[y+xy3(1+lnx)]dx=0
May answer key po ba kayo nito. Icheck ko lang po sana kung tama answers ko. Thank you po. Critical points/maxima and minima
y=4-6x+x²
y=(2x-1)²
y=2+12x-x³
y=x³-3x²-9x+20
y=x³-3x²+4x+5
y=x³-6x²+12x
y=x⁴+2x²+8x+3
y=16x+4x²-x⁴
y=x²(x-2)²
a³y=x⁴
9a³y=x(4a-x)³
a³y=x²(2a²-x²)
a³y=x³(4a-3x)
a⁵y=x⁴(3a²-2x²)
Forum posts (unless otherwise specified) licensed under a Creative Commons Licence.
Recent comments
(…