Minima maxima: Arbitrary constants for a cubic Member for 6 years Submitted by Francis June E… on Mon, 04/13/2020 - 09:11 Make the curve y=ax³+bx²+cx+d pass through the points (0,1)and (-3,7) and have a critical point at (-1,3) Ans. y=-x³-4x²-5x+1 Thanks po Tags Minima maxima Log in or register to post comments Steps: Member for 17 years 6 months Jhun Vert Mon, 04/13/2020 - 10:52 Steps: Substitute (0, 1) to the equation. Result: d = 1. Substitute (-3, 7) to the equation. Result: -27a + 9b - 3c = 6. Substitute (-1, 3) to the equation. Result: -a + b - c = 2. Differentiate and set y' to zero. Because (-1, 3) is a critical point, replace x with -1. Result: 3a - 2b + c = 0. Solve the three equations from steps (2), (3), and (4). Log in or register to post comments Paano ko po makuha yung value Member for 6 years Francis June E… Mon, 04/13/2020 - 11:45 In reply to Steps: by Jhun VertPaano ko po makuha yung value ni a at b? Eqn.2 at eqn 3 nalang po natira. 0=0 po yung eqn.4 C=-3a+2b kasi value ni c. At sinubstitute ko sa eqn. 2-4 Log in or register to post comments Eq. (1): -27a + 9b - 3c = 6 Member for 10 years 8 months Alexander Mon, 04/13/2020 - 12:49 In reply to Steps: by Jhun VertEq. (2): -27a + 9b - 3c = 6 Eq. (3): -a + b - c = 2 Eq. (4): 3a - 2b + c = 0 Eq. (2) - 3*Eq. (3) -24a + 6b = 0 6b = 24a b = 4a Eq. (3) + Eq. (4) 2a - b = 2 2a - 4a = 2 -2a = 2 a = -1 Log in or register to post comments Thank you sir Alexander and Member for 6 years Francis June E… Mon, 04/13/2020 - 13:24 In reply to Eq. (1): -27a + 9b - 3c = 6 by AlexanderThank you sir Alexander and Sir Jhun Vert Log in or register to post comments
Steps: Member for 17 years 6 months Jhun Vert Mon, 04/13/2020 - 10:52 Steps: Substitute (0, 1) to the equation. Result: d = 1. Substitute (-3, 7) to the equation. Result: -27a + 9b - 3c = 6. Substitute (-1, 3) to the equation. Result: -a + b - c = 2. Differentiate and set y' to zero. Because (-1, 3) is a critical point, replace x with -1. Result: 3a - 2b + c = 0. Solve the three equations from steps (2), (3), and (4). Log in or register to post comments
Paano ko po makuha yung value Member for 6 years Francis June E… Mon, 04/13/2020 - 11:45 In reply to Steps: by Jhun VertPaano ko po makuha yung value ni a at b? Eqn.2 at eqn 3 nalang po natira. 0=0 po yung eqn.4 C=-3a+2b kasi value ni c. At sinubstitute ko sa eqn. 2-4 Log in or register to post comments
Eq. (1): -27a + 9b - 3c = 6 Member for 10 years 8 months Alexander Mon, 04/13/2020 - 12:49 In reply to Steps: by Jhun VertEq. (2): -27a + 9b - 3c = 6 Eq. (3): -a + b - c = 2 Eq. (4): 3a - 2b + c = 0 Eq. (2) - 3*Eq. (3) -24a + 6b = 0 6b = 24a b = 4a Eq. (3) + Eq. (4) 2a - b = 2 2a - 4a = 2 -2a = 2 a = -1 Log in or register to post comments
Thank you sir Alexander and Member for 6 years Francis June E… Mon, 04/13/2020 - 13:24 In reply to Eq. (1): -27a + 9b - 3c = 6 by AlexanderThank you sir Alexander and Sir Jhun Vert Log in or register to post comments
Steps:
Member for
17 years 6 monthsSteps:
Result: d = 1.
Result: -27a + 9b - 3c = 6.
Result: -a + b - c = 2.
Result: 3a - 2b + c = 0.
Paano ko po makuha yung value
Member for
6 yearsIn reply to Steps: by Jhun Vert
Paano ko po makuha yung value ni a at b?
Eqn.2 at eqn 3 nalang po natira.
0=0 po yung eqn.4
C=-3a+2b kasi value ni c. At sinubstitute ko sa eqn. 2-4
Eq. (1): -27a + 9b - 3c = 6
Member for
10 years 8 monthsIn reply to Steps: by Jhun Vert
Eq. (2): -27a + 9b - 3c = 6
Eq. (3): -a + b - c = 2
Eq. (4): 3a - 2b + c = 0
Eq. (2) - 3*Eq. (3)
-24a + 6b = 0
6b = 24a
b = 4a
Eq. (3) + Eq. (4)
2a - b = 2
2a - 4a = 2
-2a = 2
a = -1
Thank you sir Alexander and
Member for
6 yearsIn reply to Eq. (1): -27a + 9b - 3c = 6 by Alexander
Thank you sir Alexander and Sir Jhun Vert