Submitted by Inah Mae on April 25, 2022 - 7:44pm
May answer key po ba kayo nito. Icheck ko lang po sana kung tama answers ko. Thank you po. Critical points/maxima and minima
y=4-6x+x²
y=(2x-1)²
y=2+12x-x³
y=x³-3x²-9x+20
y=x³-3x²+4x+5
y=x³-6x²+12x
y=x⁴+2x²+8x+3
y=16x+4x²-x⁴
y=x²(x-2)²
a³y=x⁴
9a³y=x(4a-x)³
a³y=x²(2a²-x²)
a³y=x³(4a-3x)
a⁵y=x⁴(3a²-2x²)
Submitted by Francis June E.... on April 13, 2020 - 8:01pm
Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).
Ans nya po is y=x³+3x²-2. Salamat po
Submitted by Francis June E.... on April 13, 2020 - 9:11am
Make the curve y=ax³+bx²+cx+d pass through the points (0,1)and (-3,7) and have a critical point at (-1,3)
Ans. y=-x³-4x²-5x+1
Thanks po
Submitted by Francis June E.... on April 12, 2020 - 8:37pm
What is the condition that the cubic y=ax³+bx²+cx+d shall have two Extremes?
Answer nya po is b²-3ac>0
Salamat po.
Submitted by Francis June E.... on April 9, 2020 - 4:53pm
Patulong po ulit ako mam/sir
Yung process po sana ulit
9a²y=x(4a+x)³
Yung ans nya po is (a,3a) maximum
Thanks in advance mam/sir
