# Minima maxima

## Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).

Submitted by Francis June E.... on April 13, 2020 - 8:01pm

Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).

Ans nya po is y=x³+3x²-2. Salamat po

## Minima maxima: Arbitrary constants for a cubic

Submitted by Francis June E.... on April 13, 2020 - 9:11am

Make the curve y=ax³+bx²+cx+d pass through the points (0,1)and (-3,7) and have a critical point at (-1,3)

Ans. y=-x³-4x²-5x+1

Thanks po

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## Minima Maxima: y=ax³+bx²+cx+d

Submitted by Francis June E.... on April 12, 2020 - 8:37pm

What is the condition that the cubic y=ax³+bx²+cx+d shall have two Extremes?

Answer nya po is b²-3ac>0

Salamat po.

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## Minima Maxima: 9a³y=x(4a-x)³

Submitted by Francis June E.... on April 9, 2020 - 4:53pm

Patulong po ulit ako mam/sir

Yung process po sana ulit

9a²y=x(4a+x)³

Yung ans nya po is (a,3a) maximum

Thanks in advance mam/sir

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- Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).
- Minima maxima: Arbitrary constants for a cubic
- Minima Maxima: y=ax³+bx²+cx+d