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- Can you help me po to solve this?
- Eliminate the Arbitrary Constants
- Required diameter of solid shaft
- Differentiate trigonometric function
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## Re: Radicals

$\sqrt{x - \sqrt{1 - x}} = 1 - \sqrt{x}$

$x - \sqrt{1 - x} = \left( 1 - \sqrt{x} \right)^2$

$x - \sqrt{1 - x} = 1 - 2\sqrt{x} + x$

$\sqrt{1 - x} = 2\sqrt{x} - 1$

$1 - x = \left( 2\sqrt{x} - 1 \right)^2$

$1 - x = 4x - 4\sqrt{x} + 1$

$4\sqrt{x} = 5x$

$16x = 25x^2$

$16 = 25x$

$x = \dfrac{16}{25}$

## Re: Radicals: Solve for x from sqrt (x - sqrt (1 - x)) = 1 -...

Pwde po ba idirect sa calcu?

## Re: Radicals: Solve for x from sqrt (x - sqrt (1 - x)) = 1 -...

In reply to Re: Radicals: Solve for x from sqrt (x - sqrt (1 - x)) = 1 -... by Jeanmagsuay

Yes...

## You can try th symbolab app.

In reply to Re: Radicals: Solve for x from sqrt (x - sqrt (1 - x)) = 1 -... by Jeanmagsuay

You can try th symbolab app. I haven't tried this problem on that app but I guess it'll work.

## Paano po i-direct sa calcu?

Paano po i-direct sa calcu?

## shift solve

In reply to Paano po i-direct sa calcu? by Angel_____ (not verified)

shift solve