Solve for $x$: $\dfrac{1}{x} + \dfrac{1}{x + 2} = 1$
Determine the value of x from the following equation:
$\dfrac{1}{x} + \dfrac{1}{x + 2} = 1$
Solve for $x$
Radicals: Solve for x from $\sqrt{x - \sqrt{1 - x}} = 1 - \sqrt{x}$
sqrt(x-sqrt(1-x)) = 1-sqrt(x)
solve for x