# Solve for $x$

## Solve for $x$: $\dfrac{1}{x} + \dfrac{1}{x + 2} = 1$

Determine the value of x from the following equation:
$\dfrac{1}{x} + \dfrac{1}{x + 2} = 1$

## Radicals: Solve for x from $\sqrt{x - \sqrt{1 - x}} = 1 - \sqrt{x}$

sqrt(x-sqrt(1-x)) = 1-sqrt(x)

solve for x