sqrt(x-sqrt(1-x)) = 1-sqrt(x)
solve for x
$\sqrt{x - \sqrt{1 - x}} = 1 - \sqrt{x}$
$x - \sqrt{1 - x} = \left( 1 - \sqrt{x} \right)^2$
$x - \sqrt{1 - x} = 1 - 2\sqrt{x} + x$
$\sqrt{1 - x} = 2\sqrt{x} - 1$
$1 - x = \left( 2\sqrt{x} - 1 \right)^2$
$1 - x = 4x - 4\sqrt{x} + 1$
$4\sqrt{x} = 5x$
$16x = 25x^2$
$16 = 25x$
$x = \dfrac{16}{25}$
Pwde po ba idirect sa calcu?
Yes...
You can try th symbolab app. I haven't tried this problem on that app but I guess it'll work.
Paano po i-direct sa calcu?
shift solve
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$\sqrt{x - \sqrt{1 - x}} = 1 - \sqrt{x}$
$x - \sqrt{1 - x} = \left( 1 - \sqrt{x} \right)^2$
$x - \sqrt{1 - x} = 1 - 2\sqrt{x} + x$
$\sqrt{1 - x} = 2\sqrt{x} - 1$
$1 - x = \left( 2\sqrt{x} - 1 \right)^2$
$1 - x = 4x - 4\sqrt{x} + 1$
$4\sqrt{x} = 5x$
$16x = 25x^2$
$16 = 25x$
$x = \dfrac{16}{25}$
Pwde po ba idirect sa calcu?
Yes...
You can try th symbolab app. I haven't tried this problem on that app but I guess it'll work.
Paano po i-direct sa calcu?
shift solve
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