Volume in the first octant bounded by the surfaces z=x+y and y=1x2

Find the volume using multiple integral in the first octant bounded by the surfaces z = x + y, y = 1 - x^2.

yU=1x2

yL=zx
 

integral_012-volume-bounded-by-surfaces.gif

 

V=10z0(yUyL)dxdz

V=10z0[(1x2)(zx)]dxdz

V=10[xx33zx+x22]z0dz

V=10(z13z3z2+12z2)dz

V=10(z13z312z2)dz

V=[z22z412z36]10

V=1211216

V=14 unit3