**Problem 346**

A boom AB is supported in a horizontal position by a hinge A and a cable which runs from C over a small pulley at D as shown in Fig. P-346. Compute the tension T in the cable and the horizontal and vertical components of the reaction at A. Neglect the size of the pulley at D.

**Solution 346**

## Click here to show or hide the solution

$4(\frac{2}{\sqrt{5}}T) = 2(200) + 6(100)$

$T = 279.51 \, \text{ lb}$ *answer*

$\Sigma F_V = 0$

$A_V + \frac{2}{\sqrt{5}}T = 200 + 100$

$A_V + \frac{2}{\sqrt{5}}(279.51) = 300$

$A_V = 50 \, \text{ lb}$ *answer*

$\Sigma F_H = 0$

$A_H = \frac{1}{\sqrt{5}}T$

$A_H = \frac{1}{\sqrt{5}}(279.51)$

$A_H = 125 \, \text{ lb}$ *answer*