## Problem 355 | Equilibrium of Non-Concurrent Force System

Problem 355
Determine the reactions at A and B on the Fink truss shown in Fig. P-355. Members CD and FG are respectively perpendicular to AE and BE at their midpoints. ## Problem 354 | Equilibrium of Non-Concurrent Force System

Problem 354
Compute the total reactions at A and B on the truss shown in Fig. P-354. ## Problem 352 | Equilibrium of Non-Concurrent Force System

Problem 352
A pulley 4 ft in diameter and supporting a load 200 lb is mounted at B on a horizontal beam as shown in Fig. P-352. The beam is supported by a hinge at A and rollers at C. Neglecting the weight of the beam, determine the reactions at A and C. ## Problem 350 | Equilibrium of Non-Concurrent Force System

Problem 350
Compute the total reactions at A and B for the truss shown in Fig. P-350. ## Problem 349 | Equilibrium of Non-Concurrent Force System

Problem 349
The truss shown in Fig. P-349 is supported on roller at A and hinge at B. Solve for the components of the reactions. Problem 348 | Equilibrium of Non-Concurrent Force System Jhun Vert Sun, 04/19/2020 - 11:39 am

Problem 348
The frame shown in Fig. P-348 is supported in pivots at A and B. Each member weighs 5 kN/m. Compute the horizontal reaction at A and the horizontal and vertical components of the reaction at B. ## Problem 347 | Equilibrium of Non-Concurrent Force System

Problem 347
Repeat Problem 346 if the cable pulls the boom AB into a position at which it is inclined at 30° above the horizontal. The loads remain vertical. ## Problem 346 | Equilibrium of Non-Concurrent Force System

Problem 346
A boom AB is supported in a horizontal position by a hinge A and a cable which runs from C over a small pulley at D as shown in Fig. P-346. Compute the tension T in the cable and the horizontal and vertical components of the reaction at A. Neglect the size of the pulley at D. ## Equilibrium of Non-Concurrent Force System

There are three equilibrium conditions that can be used for non-concurrent, non-parallel force system.

The sum of all forces in the x-direction or horizontal is zero.

$\Sigma F_x = 0$   or   $\Sigma F_H = 0$

Resultant of Non-Concurrent Force System Jhun Vert Sat, 04/18/2020 - 10:35 am

The resultant of non-concurrent force system is defined according to magnitude, inclination, and position.

The magnitude of the resultant can be found as follows

$R_x = \Sigma F_x$

$R_y = \Sigma F_y$

$R = \sqrt{{R_x}^2 + {R_y}^2}$