Problem 352 | Equilibrium of Non-Concurrent Force System

Problem 352
A pulley 4 ft in diameter and supporting a load 200 lb is mounted at B on a horizontal beam as shown in Fig. P-352. The beam is supported by a hinge at A and rollers at C. Neglecting the weight of the beam, determine the reactions at A and C.
 

Pulley mounted at the midspan of simple beam

 

Problem 346 | Equilibrium of Non-Concurrent Force System

Problem 346
A boom AB is supported in a horizontal position by a hinge A and a cable which runs from C over a small pulley at D as shown in Fig. P-346. Compute the tension T in the cable and the horizontal and vertical components of the reaction at A. Neglect the size of the pulley at D.
 

Cable and boom structure

 

Equilibrium of Non-Concurrent Force System

There are three equilibrium conditions that can be used for non-concurrent, non-parallel force system.
 

The sum of all forces in the x-direction or horizontal is zero.

$\Sigma F_x = 0$   or   $\Sigma F_H = 0$

 

Resultant of Non-Concurrent Force System

The resultant of non-concurrent force system is defined according to magnitude, inclination, and position.
 

The magnitude of the resultant can be found as follows

$R_x = \Sigma F_x$

$R_y = \Sigma F_y$

$R = \sqrt{{R_x}^2 + {R_y}^2}$