Unit weight of wood
γ=8kNm3×1000 N1 kN×(1 m1000 mm)3
γ=0.000008 N/mm3
wo=3000400+0.000008(100d)
wo=7.5+0.0008d N/mm
Part 1: Based on allowable bending stress (Fb = 24 MPa)
M=woL28
M=(7.5+0.0008d)(50002)8
M=3125000(7.5+0.0008d) N⋅mm
Fb=6Mbd2
24=6[3125000(7.5+0.0008d)]100d2
d=245.2 mm answer
Part 2: Based on allowable shear stress (Fv = 1.24 MPa)
V=R=woL2
V=(7.5+0.0008d)(5000)2
V=2500(7.5+0.0008d)
Fv=3V2bd
1.24=3[2500(7.5+0.0008d)]2(100d)
d=232.44 mm answer
Part 3: Based on allowable deflection (δ = L/240)
δ=L240=5000240
δ=1256mm
δ=5woL4384EI
1256=5(7.5+0.0008d)(50004)384(18600)(100d312)
d=268.9 mm answer