DE
(x²+4) y' + 3 xy = x
- Read more about DE
- Log in or register to post comments
| Forum | Topics | Posts | Last post |
|---|---|---|---|
|
No new posts
|
|||
|
No new posts
|
58 | 172 | By Godofredo 3 weeks ago |
|
No new posts
|
26 | 80 | By Engr Jaydee 11 months 1 week ago |
|
No new posts
|
74 | 207 | By fitzmerl duron 1 year 8 months ago |
|
No new posts
|
3 | 6 | By Jhun Vert 5 years 1 month ago |
|
No new posts
|
18 | 50 | By Jhun Vert 3 years 9 months ago |
|
No new posts
|
21 | 41 | By Jhun Vert 1 year 5 months ago |
|
No new posts
|
|||
|
No new posts
|
122 | 328 | By Jhun Vert 3 weeks 1 day ago |
|
No new posts
|
31 | 82 | By Jhun Vert 1 year 6 months ago |
|
No new posts
|
40 | 120 | By Jhun Vert 1 year 5 months ago |
|
No new posts
|
9 | 19 | By agentcollins 4 years 6 months ago |
|
No new posts
|
|||
|
No new posts
|
93 | 206 | By Jhun Vert 3 weeks 2 days ago |
|
No new posts
|
75 | 175 | By Jhun Vert 1 year 8 months ago |
|
No new posts
|
|||
|
No new posts
|
7 | 34 | By fitzmerl duron 1 year 6 months ago |
|
No new posts
|
46 | 86 | By inzenyrp 10 months 3 weeks ago |
(x²+4) y' + 3 xy = x
Ask ko lang po? Bat wala po kayong Shear and Moment in Frames?
How do you calculate NPV for a model with single payment compound amount scenario.

1434 (fl. singer 4th edition)
Determine the maximum torque that can be applied at 1.0 m from the right end of the shaft, without causing excessive rotation.
A simple supported right-angle triangle truss of 1/2( 5 x 12 ) meter square, is subjected with 50KN and 25KN at the mid-span and top end of the truss respectively. The truss is having two internal members one acting horizontal at the mid-span and the other acting diagonal from support A to joint at a point on the slanted side of right angle triangle.
Taking into account that the pined support is on the right and the roller on the left.
You are required to check the determinant and compute the reactions of this truss.
The radial stress p at distance r for the axis of the thick cylinder subjected to internal pressure is given by p + r (dp/dr) = A − p where A is a constant. If p = p0 at the inner wall r = r1 and is negligible (p = 0) at the outer wall r = r2 find an expression for p.
(xy + (y/x) + (3/x) -2) dy + y2 dx = 2(1+(y/x))dx
Please help me again to solve this.
(e2y-ycosxy)dx-y(1-x2)dy=0
find a general solution
dx/dy =[ -2x (csc 2y – 2x3 cos 2y)] / sec 2y
Hi! Pahelp please? Anyone who has a good heart huhuhu. I badly need your help. Anyone who can answer this? I mean with the process.
The collar has a mass of 3kg and is supported on the rod having a coefficient of kinetic friction Uk=0.4. The attached spring has an unstretched length of 0.2m and stiffness k=50N/m. Determine the speed of the collar after the applied force F=200N causes it to be displaced s=1.5m from pt. A. When s=0 the collar is held at rest?
What is the process?
Forum posts (unless otherwise specified) licensed under a Creative Commons Licence.
Recent comments