# Discussion on: Problem 535 | Friction on Wedges

Submitted by Benjamin_Molina on August 16, 2015 - 8:16am

Following is a discussion on the Reviewer item titled: Problem 535 | Friction on Wedges. Feel free to add your own comments!

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## #535 FRICTION WEDGE

Two questions, why is Phi + 1/2 Alpha =90 degrees. Where did we get the 90 degrees? Sin Alpha = Sin (180 degrees -2 Phi), How did we get sine? Thank you.

## Re: #535 FRICTION WEDGE

arccos of zero = 90.

You can use Cos or Tan or Log or +x or -x or anything you want to do both sides of the equation. Sine however will serve the purpose.

## Re: #535 FRICTION WEDGE

That clarifies everything. Thank you Mr. Verterra.

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