Discussion on: Problem 535 | Friction on Wedges
Following is a discussion on the Reviewer item titled: Problem 535 | Friction on Wedges. Feel free to add your own comments!
Following is a discussion on the Reviewer item titled: Problem 535 | Friction on Wedges. Feel free to add your own comments!
#535 FRICTION WEDGE
Two questions, why is Phi + 1/2 Alpha =90 degrees. Where did we get the 90 degrees? Sin Alpha = Sin (180 degrees -2 Phi), How did we get sine? Thank you.
Re: #535 FRICTION WEDGE
In reply to #535 FRICTION WEDGE by Benjamin_Molina
arccos of zero = 90.
You can use Cos or Tan or Log or +x or -x or anything you want to do both sides of the equation. Sine however will serve the purpose.
Re: #535 FRICTION WEDGE
In reply to Re: #535 FRICTION WEDGE by Jhun Vert
That clarifies everything. Thank you Mr. Verterra.