Following is a discussion on the Reviewer item titled: Problem 535 | Friction on Wedges. Feel free to add your own comments!

August 16, 2015 - 8:16am

#1
Discussion on: Problem 535 | Friction on Wedges

Following is a discussion on the Reviewer item titled: Problem 535 | Friction on Wedges. Feel free to add your own comments!

Two questions, why is Phi + 1/2 Alpha =90 degrees. Where did we get the 90 degrees? Sin Alpha = Sin (180 degrees -2 Phi), How did we get sine? Thank you.

arccos of zero = 90.

You can use Cos or Tan or Log or +x or -x or anything you want to do both sides of the equation. Sine however will serve the purpose.

That clarifies everything. Thank you Mr. Verterra.

## Add new comment