Discussion on: Problem 535 | Friction on Wedges
Submitted by Benjamin_Molina on August 16, 2015 - 8:16am
Following is a discussion on the Reviewer item titled: Problem 535 | Friction on Wedges. Feel free to add your own comments!
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#535 FRICTION WEDGE
Two questions, why is Phi + 1/2 Alpha =90 degrees. Where did we get the 90 degrees? Sin Alpha = Sin (180 degrees -2 Phi), How did we get sine? Thank you.
Re: #535 FRICTION WEDGE
arccos of zero = 90.
You can use Cos or Tan or Log or +x or -x or anything you want to do both sides of the equation. Sine however will serve the purpose.
Re: #535 FRICTION WEDGE
That clarifies everything. Thank you Mr. Verterra.
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