Discussion on: Problem 354 | Equilibrium of Non-Concurrent Force System

Following is a discussion on the Reviewer item titled: Problem 354 | Equilibrium of Non-Concurrent Force System.
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In reply to by Renz Anjo Caparas

The number 3 is the vertical distance between point B and the point of application of 22.4 kN load (at the tip of the arrowhead). The (1/squareroot of 5)×22.4 is the horizontal component of 22.4 kN. Let P = 22.4 kN, by ratio and proportion:

horizontal over inclined
$\dfrac{P_x}{22.4} = \dfrac{1}{\sqrt{5}}$

$P_x = (\frac{1}{\sqrt{5}})(22.4)$