Active forum topics
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Eliminate the Arbitrary Constants
- Law of cosines
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Integration of 4x^2/csc^3x√sinxcosx dx
- application of minima and maxima
- Sight Distance of Vertical Parabolic Curve
- Application of Differential Equation: Newton's Law of Cooling
New forum topics
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Integration of 4x^2/csc^3x√sinxcosx dx
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Newton's Law of Cooling
- Law of cosines
- Can you help me po to solve this?
- Eliminate the Arbitrary Constants
- Required diameter of solid shaft
Recent comments
- Use integration by parts for…2 weeks 6 days ago
- need answer2 weeks 6 days ago
- Yes you are absolutely right…3 weeks 2 days ago
- I think what is ask is the…3 weeks 2 days ago
- $\cos \theta = \dfrac{2}{…3 weeks 3 days ago
- Why did you use (1/SQ root 5…3 weeks 3 days ago
- How did you get the 300 000pi3 weeks 3 days ago
- It is not necessary to…3 weeks 4 days ago
- Draw a horizontal time line…4 weeks 1 day ago
- Mali po ang equation mo…1 month 1 week ago
Re: area of the region bounded
Re: area of the region bounded
Re: area of the region bounded
The equation $y = x^2$ is an upward parabola and the $y = \sqrt{x}$ is a rightward parabola. The two has vertex at the origin and they meet at point (1, 1). The required area is dotted region in the figure below:
The area of the rectangular element is y dx, and y is the difference between the top end and bottom end of the strip. In equation,
$dA = y \, dx = (y_U - y_L) \, dx$
You sum (integrate) it up and you're good to go.
Re: area of the region bounded
In reply to Re: area of the region bounded by Jhun Vert
Thank you po..