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- Ceva’s Theorem Is More Than a Formula for Concurrency
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- Inverse Trigo
- Problems in progression
- General Solution of $y' = x \, \ln x$
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Re: area of the region bounded
Re: area of the region bounded
Re: area of the region bounded
The equation $y = x^2$ is an upward parabola and the $y = \sqrt{x}$ is a rightward parabola. The two has vertex at the origin and they meet at point (1, 1). The required area is dotted region in the figure below:
The area of the rectangular element is y dx, and y is the difference between the top end and bottom end of the strip. In equation,
$dA = y \, dx = (y_U - y_L) \, dx$
You sum (integrate) it up and you're good to go.
Re: area of the region bounded
In reply to Re: area of the region bounded by Jhun Vert
Thank you po..