## Active forum topics

- Eliminate the Arbitrary Constants
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- Special products and factoring
- Integration of 4x^2/csc^3x√sinxcosx dx
- application of minima and maxima
- Sight Distance of Vertical Parabolic Curve
- Application of Differential Equation: Newton's Law of Cooling
- Minima maxima: a²y = x⁴
- Trim and stability

## New forum topics

- Integration of 4x^2/csc^3x√sinxcosx dx
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Newton's Law of Cooling
- Law of cosines
- Can you help me po to solve this?
- Eliminate the Arbitrary Constants
- Required diameter of solid shaft
- Differentiate trigonometric function
- Integration $\displaystyle \int \sec 2x ~ dx$

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## i love you sir

i love you sir

## Eewwww... so gay!!! hahaha

In reply to i love you sir by Kayro Mendoza …

Eewwww... so gay!!! hahaha

## Hi sir I guess there is no

Hi sir I guess there is no possible answer or cant solved this.

Supposed that n is greater than 1 let say 2, then assumed that X = 1 so 1=1^2 this could not be X>X^2.

If X=2 ; then 2 is not greater than 2^2

My answer is no possible answer..cant solve

Even if I apply log cant solve. I guess no sufficient number of X is greater than X^n when n is a positive integer greater than 1.

Please correct me if I am wrong. Thank you your website is a great help for my self review in our upcoming SPLBE for Engineering board exam here in the middle east.

## This can be possible for x >

In reply to Hi sir I guess there is no by esmilitar

This can be possible for x > 0 but x < 1. Example: 1/2 > 1/4.

Thank you for the feed back, we are happy it helps you in certain way. We are starting to upload past board for CE. Our sole purpose is to help graduates of CE in the middle east but no PRC license yet. We are at a very early stage of doing it; less than a month. The contents of past CE board is very few but it can give you a glimpse of what type of problems are coming.

## Thank you sir.

In reply to This can be possible for x > by Jhun Vert

Thank you sir.

## x<1

0 x 1

## i love you sir

In reply to x<1 by Kayro Mendoza …

i love you sir... hahaha