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- Ceva’s Theorem Is More Than a Formula for Concurrency
- The Chain Rule Explained: Don't Just Memorize, Visualize It
- The Intuition Behind Integration by Parts (Proof & Example)
- Statics
- Calculus
- Hydraulics: Rotating Vessel
- Inverse Trigo
- Problems in progression
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
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i love you sir
i love you sir
Eewwww... so gay!!! hahaha
In reply to i love you sir by Kayro Mendoza …
Eewwww... so gay!!! hahaha
Hi sir I guess there is no
Hi sir I guess there is no possible answer or cant solved this.
Supposed that n is greater than 1 let say 2, then assumed that X = 1 so 1=1^2 this could not be X>X^2.
If X=2 ; then 2 is not greater than 2^2
My answer is no possible answer..cant solve
Even if I apply log cant solve. I guess no sufficient number of X is greater than X^n when n is a positive integer greater than 1.
Please correct me if I am wrong. Thank you your website is a great help for my self review in our upcoming SPLBE for Engineering board exam here in the middle east.
This can be possible for x >
In reply to Hi sir I guess there is no by esmilitar
This can be possible for x > 0 but x < 1. Example: 1/2 > 1/4.
Thank you for the feed back, we are happy it helps you in certain way. We are starting to upload past board for CE. Our sole purpose is to help graduates of CE in the middle east but no PRC license yet. We are at a very early stage of doing it; less than a month. The contents of past CE board is very few but it can give you a glimpse of what type of problems are coming.
Thank you sir.
In reply to This can be possible for x > by Jhun Vert
Thank you sir.
x<1
0 x 1
i love you sir
In reply to x<1 by Kayro Mendoza …
i love you sir... hahaha