# Solids for which V=(mean B)h

Hello.. and good evening.

I would like to know how to solve for the area of the mid-section of this prismatoid. I tried solving for the volume and I got an answer of 375 cu. ft. but according to Kern and Bland's book the real answer is 310 cu.ft. I guess I made a mistake in solving it.

Can I know the complete solution and the illustration of the top view of the prismatoid's mid-section? Thank you very much to whoever will answer my question. It would be a great help for me.

Problem: Edge AB is perpendicular to the bases BDC and AEF. Find the volume of the solid, if BD is parallel to AE.

Figure: http://imgur.com/7YvdHkS

## Re: Solids for which V=(mean B)h

LI is parallel to GH, thus, GHIL is a trapezoid.

GH = 7/2 = 3.5

HI = 14/2 = 7

JK = 8/2 = 4

IJ = 6/2 = 3

IK = 7/2 = 3.5

KL = 12/2 = 6

LG = 13/2 = 6.5

IL = (7 + 12)/2 = 9.5

IL = IK + LG = 3.5 + 6 = 9.5 (okay)

Area of the mid section = Area of GHIL + Area of IJK

## Re: Solids for which V=(mean B)h

In reply to Re: Solids for which V=(mean B)h by Jhun Vert

ano tama sagot lumalabas kc sa sagot ko..V=360.59 hehehe