Active forum topics
- Inverse Trigo
- General Solution of y′=xlnx
- engineering economics: construct the cash flow diagram
- Eliminate the Arbitrary Constants
- Law of cosines
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Integration of 4x^2/csc^3x√sinxcosx dx
- application of minima and maxima
- Sight Distance of Vertical Parabolic Curve
New forum topics
- Inverse Trigo
- General Solution of y′=xlnx
- engineering economics: construct the cash flow diagram
- Integration of 4x^2/csc^3x√sinxcosx dx
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Newton's Law of Cooling
- Law of cosines
- Can you help me po to solve this?
- Eliminate the Arbitrary Constants
Recent comments
- Solve mo ang h manually…3 days 17 hours ago
- Paano kinuha yung height na…3 days 17 hours ago
- It's the unit conversion…2 weeks 1 day ago
- Refer to the figure below…1 week 2 days ago
- Yes.4 months ago
- Sir what if we want to find…4 months ago
- Hello po! Question lang po…4 months 3 weeks ago
- 400000=120[14π(D2−10000)]
(…5 months 3 weeks ago - Use integration by parts for…6 months 3 weeks ago
- need answer6 months 3 weeks ago
Re: Lead needed to coat a cable
Radius of uncoated cable = 55/2 = 27.5 mm = 0.0275 m
Radius of coated cable = 55/2 + 4 = 31.5 mm = 0.0315 m
Length of cable = 5000 m
Required volume of lead
V=π(0.03152−0.02752)(5000)=1.18π m3
Required mass of lead
m=ρV=(11.4×103)(1.18π)=42,260.70 kg
Re: Lead needed to coat a cable
Thank you, sir!! :)