Member for 10 years 11 months By MichMaganda, 9 May, 2015 How much lead is needed to coat a cable, 55mm in diameter, if the cable is 5km long and the lead coat is 4mm thick. 11.4x10^3 kg/m^3 for the density of the lead. Member for 17 years 6 months Re: Lead needed to coat a cable Radius of uncoated cable = 55/2 = 27.5 mm = 0.0275 m Radius of coated cable = 55/2 + 4 = 31.5 mm = 0.0315 m Length of cable = 5000 m Required volume of lead $V = \pi (0.0315^2 - 0.0275^2)(5000) = 1.18\pi ~ \text{ m}^3$ Required mass of lead $m = \rho V = (11.4 \times 10^3)(1.18\pi) = 42,260.70 ~ \text{ kg}$ Member for 10 years 11 months Re: Lead needed to coat a cable Thank you, sir!! :) Log in or register to post comments
Member for 17 years 6 months Re: Lead needed to coat a cable Radius of uncoated cable = 55/2 = 27.5 mm = 0.0275 m Radius of coated cable = 55/2 + 4 = 31.5 mm = 0.0315 m Length of cable = 5000 m Required volume of lead $V = \pi (0.0315^2 - 0.0275^2)(5000) = 1.18\pi ~ \text{ m}^3$ Required mass of lead $m = \rho V = (11.4 \times 10^3)(1.18\pi) = 42,260.70 ~ \text{ kg}$
Member for
17 years 6 monthsRe: Lead needed to coat a cable
Radius of uncoated cable = 55/2 = 27.5 mm = 0.0275 m
Radius of coated cable = 55/2 + 4 = 31.5 mm = 0.0315 m
Length of cable = 5000 m
Required volume of lead
$V = \pi (0.0315^2 - 0.0275^2)(5000) = 1.18\pi ~ \text{ m}^3$
Required mass of lead
$m = \rho V = (11.4 \times 10^3)(1.18\pi) = 42,260.70 ~ \text{ kg}$
Member for
10 years 11 monthsRe: Lead needed to coat a cable
Thank you, sir!! :)