Differentiate trigonometric function

Hello everyone! I need some help again. Can anyone derive this problem with steps?

d/dx ((tan2x)+(sec2x))
Thank you.

The differentiation you need is direct from the following formulas:

  1. d(tanu)=sec2u du
  2. d(secu)=secutanu du

From your equation, u=2x from which du=2, hence,
ddx[tan2x+sec2x]=2sec22x+2sec2xtan2x