Laplace

Laplace of e5t+1(t sin (t))

L(sint)=1s2+1L(tsint)=(1s2+1)=2s(s2+1)2L(te5tsint)=2(s5)[(s5)2+1]2L(te5t+1sint)=2e(s5)[(s5)2+1]2