Problem Assuming specific weight of air to be constant at 12 N/m3, what is the approximate height of Mt. Banahaw if a mercury barometer at the base of the mountain reads 654 mm and at the same time another mercury barometer at the top of the mountain reads 480 mm.
Answer Key
Solution
$h_b = 174 ~ \text{mm Hg}$
Approximate height of Mt. Banahaw $h = h_b \times \dfrac{\gamma_{\text{mercury}}}{\gamma_{\text{air}}}$
$h = 0.174 \times \dfrac{13.6(9810)}{12}$
$h = 1934.532 ~ \text{m}$ ← answer
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