$p_{absolute} = p_{atmospheric} + p_{gauge}$
$p_{absolute} = 101.325 + (\gamma h)_\text{mercury}$
$p_{absolute} = 101.325 + s_\text{mercury}\gamma_\text{water}h_\text{mercury}$
$p_{absolute} = 101.325 + 13.6(9.81)(0.2)$
$p_{absolute} = 128.0082 ~ \text{kPa}$ ← Answer: [ C ]
