Problem 264
Completely determine the resultant with respect to point O of the force system shown in Fig. P-264.
 

Problem 263
Determine the resultant of the force system shown in Fig. P-263 and its x and y intercepts.
 

Problem 262
Determine completely the resultant of the forces acting on the step pulley shown in Fig. P-262.
 

Problem 260
The effect of a certain non-concurrent force system is defined by the following data: ΣF_x = +90 kN, ΣF_y = -60 kN, and ΣM_O = 360 kN·m counterclockwise. Determine the point at which the resultant intersects the x-axis.
 

The resultant of non-concurrent force system is defined according to magnitude, inclination, and position.
 

The magnitude of the resultant can be found as follows

Problem 258
Replace the system of forces shown in Fig. P-258 by an equivalent force through O and a couple acting through A and B. Solve if the forces of the couple are (a) horizontal and (b) vertical.
 

Problem 257
Replace the system of forces acting on the frame in Fig. P-257 by a resultant R at A and a couple acting horizontally through B and C.
 

Problem 256
A vertical shaft AB is 5 ft long and bolted to a rigid support at its lower end A. At its upper end B is attached a horizontal bar BC which is 2 ft long. At the end of C is applied a force P = 180 lb. Force P is perpendicular to the plane containing points A, B, and C. Determine the twisting effect of P on the shaft AB and the bending effect at point A.
 

Problem 255
A short compression member carries an eccentric load P = 200 lb situated 2 in. from the axis of the member, as shown in Fig. P-225. In strength of materials it is learned that the internal stresses are determined from the equivalent axial load and couple into which P may be resolved. Determine the equivalent axial load and couple.
 

Problem 253
In Fig. P-253 a system of forces reduces to downward vertical force 400 lb through A plus a counterclockwise couple of 800 lb·ft. Determine the single force that will produce an equivalent effect.