From the Napier's circle (SIN-TAAD rule for a)
sina=tanbtanˉD
sin14∘=tanbtan(90∘−30∘)
tanb=sin14∘tan60∘
b=7∘57′
From triangle NAC (Cosine Law for Sides)
cosb=cos90∘cos90∘+sin90∘sin90∘cosα
cos7∘57′=0(0)+1(1)cosα
α=7∘57′
θ=121.5∘−α
θ=121.5∘−7∘57′
θ=113.55∘
Thus, the airplane will pass the equator at 113° 33' East of the prime meridian. answer: C