Please help me answer
∫dx/cos(x)sin(x)
$\displaystyle \int \dfrac{dx}{\cos x \, \sin x} = 2\int \dfrac{dx}{2\cos x \, \sin x}$
$= 2\displaystyle \int \dfrac{dx}{\sin 2x}$
$= 2\displaystyle \int \csc 2x \, dx$
$= \displaystyle \int \csc 2x \, (2 \, dx)$
$= \ln (\csc 2x - \cot 2x) + C$ answer
More information about text formats
Follow @iMATHalino
MATHalino
$\displaystyle \int \dfrac{dx}{\cos x \, \sin x} = 2\int \dfrac{dx}{2\cos x \, \sin x}$
$= 2\displaystyle \int \dfrac{dx}{\sin 2x}$
$= 2\displaystyle \int \csc 2x \, dx$
$= \displaystyle \int \csc 2x \, (2 \, dx)$
$= \ln (\csc 2x - \cot 2x) + C$ answer
Add new comment