(3-x)dx/ (x^2-6x-9)^5/2
You can use power formula: $\displaystyle \int \dfrac{(3 - x) \, dx}{(x^2 - 6x - 9)^{5/2}}$
$= \displaystyle \int (x^2 - 6x - 9)^{-5/2} \, (3 - x) \, dx$
$= \displaystyle -\dfrac{1}{2} \int (x^2 - 6x - 9)^{-5/2} \, [ \, -2(3 - x) \, ] \, dx$
$= \displaystyle -\dfrac{1}{2} \int (x^2 - 6x - 9)^{-5/2} \, (2x - 6) \, dx$
More information about text formats
Follow @iMATHalino
MATHalino
You can use power formula:
$\displaystyle \int \dfrac{(3 - x) \, dx}{(x^2 - 6x - 9)^{5/2}}$
$= \displaystyle \int (x^2 - 6x - 9)^{-5/2} \, (3 - x) \, dx$
$= \displaystyle -\dfrac{1}{2} \int (x^2 - 6x - 9)^{-5/2} \, [ \, -2(3 - x) \, ] \, dx$
$= \displaystyle -\dfrac{1}{2} \int (x^2 - 6x - 9)^{-5/2} \, (2x - 6) \, dx$
Add new comment