Active forum topics
- Hydraulics: Rotating Vessel
- Inverse Trigo
- Application of Differential Equation: Newton's Law of Cooling
- Problems in progression
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Eliminate the Arbitrary Constants
- Law of cosines
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
New forum topics
- Hydraulics: Rotating Vessel
- Inverse Trigo
- Problems in progression
- General Solution of $y' = x \, \ln x$
- engineering economics: construct the cash flow diagram
- Integration of 4x^2/csc^3x√sinxcosx dx
- Maxima and minima (trapezoidal gutter)
- Special products and factoring
- Newton's Law of Cooling
- Find the roots of the quadratic equation by differentiation method
Recent comments
- Bakit po nagmultiply ng 3/4…3 weeks 3 days ago
- Determine the least depth…10 months 3 weeks ago
- Solve mo ang h manually…3 weeks 3 days ago
- Paano kinuha yung height na…11 months ago
- It's the unit conversion…11 months 1 week ago
- Refer to the figure below…11 months 1 week ago
- where do you get the sqrt413 weeks 3 days ago
- Thank you so much3 weeks 2 days ago
- How did you get the 2.8 mins…3 weeks 2 days ago
- How did you get the distance…3 weeks 2 days ago



Re: How do I work out the area?
of the shaded area sorry
Re: How do I work out the area?
If R = radius of outer circle and r = radius of inner circle, the shaded area can be fround by $A = \frac{1}{4}\pi (R^2 - r^2)$, assuming R and r are given directly or indirectly.