Case II Triangle problems
Why in case II triangle, wherein two sides and an angle opposite to one of them given (for example: a,b,A), and \(a > b sin A\) and \(a b\), the acute triangle is computed first using sine law before the obtuse triangle?
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hmmm....I don't understand...
hmmm....I don't understand....
Yung tanong nyo po ay hindi ko maintindihan......