strength of materials: normal stress of hollow circular tube

A hollow circular tube of inner radius 12.6 inches and a thickness
of 0.5 inches is subjected to a load of 48 kips. Determine the normal
stress.

Jhun Vert's picture

Because it is not stated in the problem, let us assume that the 48 kips is an axial load.

Solution
Inner radius, $r = 12.6 ~ \text{inches}$
Outer radius, $R = 12.6 + 0.5 = 13.1 ~ \text{inches}$
 

Calculate the cross-sectional area of the tube:
$A = \pi (R^2 - r^2)$
 

Calculate the normal stress.
$\sigma = \dfrac{P}{A}$ where $P = 48^k$
 

Your answer will be in the unit ksi (kilopound per square inch).
 

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