# Rectangular

Submitted by MichMaganda on May 10, 2015 - 8:59am

A rectangular container, with a **height of 24 in.**, contains **44.9 gal of water when it is full**. A stick is placed diagonally from one corner of the upper base as shown. If **BC = 10in**., **AC= 25in**. and is a point indicating the water level, find the height and volume of the liquid in the container.

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## $\dfrac{h_w}{BC} = \dfrac{24}

$\dfrac{h_w}{BC} = \dfrac{24}{AC}$

$\dfrac{h_w}{10} = \dfrac{24}{25}$

$h_w = 9.6 ~ \text{in.}$

When full

$V = A_b \times h$

$44.9 ~ \text{gal} \left( \dfrac{231 ~ \text{in.}^3}{1 ~ \text{gal}} \right) = A_b \times 24$

$A_b = 432.1625 ~ \text{in.}^2$

Volume of water

$V_w = A_b \times h_w$

$V_w = 432.1625 \times 9.6$

$V_w = 4148.76 ~ \text{in.}^3$

$V_w = 4148.76 ~ \text{in.}^3 \left( \dfrac{1 ~ \text{gal}}{231 ~ \text{in.}^3} \right)$

$V_w = 17.96 ~ \text{gal}$