A rectangular container, with a **height of 24 in.**, contains **44.9 gal of water when it is full**. A stick is placed diagonally from one corner of the upper base as shown. If **BC = 10in**., **AC= 25in**. and is a point indicating the water level, find the height and volume of the liquid in the container.

# Rectangular

May 10, 2015 - 8:59am

#1
Rectangular

## New forum topics

- Differential equations: Newton's Law of Coolin
- I need guidance in designing a beam supporting specified ultimate moment of 1100 kN.m (doubly reinforced beam)
- I need guidance in solving the ultimate moment capacity (doubly reinforced beam)
- I need guidance in solving the balance steel area
- Please help me solve this problem using WSD (Working Stress Design) Method
- Physics: Uniform Motion
- Rescue at Sea
- Using two pumps
- Emptying a Tank
- Speed of a Plane

$\dfrac{h_w}{BC} = \dfrac{24}{AC}$

$\dfrac{h_w}{10} = \dfrac{24}{25}$

$h_w = 9.6 ~ \text{in.}$

When full

$V = A_b \times h$

$44.9 ~ \text{gal} \left( \dfrac{231 ~ \text{in.}^3}{1 ~ \text{gal}} \right) = A_b \times 24$

$A_b = 432.1625 ~ \text{in.}^2$

Volume of water

$V_w = A_b \times h_w$

$V_w = 432.1625 \times 9.6$

$V_w = 4148.76 ~ \text{in.}^3$

$V_w = 4148.76 ~ \text{in.}^3 \left( \dfrac{1 ~ \text{gal}}{231 ~ \text{in.}^3} \right)$

$V_w = 17.96 ~ \text{gal}$