# Discussion on: Solution to Problem 503 | Flexure Formula

Submitted by Benjamin_Molina on September 7, 2015 - 7:55am

Following is a discussion on the Reviewer item titled: Solution to Problem 503 | Flexure Formula. Feel free to add your own comments!

- Add new comment
- 154 reads

## Flexure Formula #503

Mr. Verterra,

I need some clarification on the location of maximum moment. I did some computation on my own and I think (using the parabolic square formula, a^2/R1=

L^2/R1=R2) I think max. moment occurs at x = 3.46. Also, how come again we are using I = bh^3/12 and not bh^3/3. Kindly clarify. Thank you in advance.

## Re: Discussion on: Solution to Problem 503 | Flexure Formula

The beam is a cantilever with downward triangular load. Generally, the maximum moment of cantilever beam will occur at the fixed support. At the point you mention, x = 3.46 m from the free end, the moment is only 1150 N-m, while at the fixed support, M = 6000 N-m.

For the moment of inertia, the one you are going to use for the bending formula f

_{b}= Mc/I is the moment of inertia about the neutral axis. The formula I = bh^{3}/3 is the moment of inertia about the base b of the rectangle, while the moment of inertia at the neutral axis is given by I = bh^{3}/12.## Add new comment