Discussion on: Advance Engineering Mathematics
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MATHalinoEngineering Math Review
Maclaurin's Series
Please Help!!
Help us find the Maclaurin's series of:
ln tanx
Re: Maclaurin's Series
In reply to Maclaurin's Series by Dyjin
Oh ! I am also looking for the answers of some power series equation
Re: Maclaurin's Series
In reply to Maclaurin's Series by Dyjin
f(x)=ln(tan(x)
f(x)=ln(tan(x)) - f(0)=0
f^1(x)=sec^2(x)/tan(x) - f(0)=0
:
.
f(x)=ln(tan(x))=0/0!+0/1!+...+0^n/n!+...
Therefore,
ln(tan(x))=Summation of (0^n/n!) with a lower limit of 0 and upper limit of infinity.