Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).
Ans nya po is y=x³+3x²-2. Salamat po
Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).
April 13, 2020 - 8:01pm
#1
Francis June E....
Make the curve y=ax³+bx²+cx+d have a critical point at (0,-2) and also be a tangent to the line 3x+y+3=0 at (-1,0).
Substitute (0, -2) to the given
Result: d = -2
Substitute (-1, 0) to the given
Result: -a + b - c = 1 ← Eq. (i)
Differentiate
Result: y' = 3ax2 + 2bx + c ← Eq. (ii)
Set y' = 0 at (0, -2)
Result: c = 0
Differentiate the line
Result: y' = -3
Set y' = -3 at (-1, 0) to Eq. (ii)
Result: 3a - 2b = -3 ← Eq. (iii)
Solve Eq. (i) and Eq. (iii) to find a and b.
-a+b-c=2 po sir sa Eqn 1. D=-2 po.
Thanks sir
D ko po makuha values nila sir.
Nakuha ko na po sir. Salamat po
Di na ako nag double check sa solution. I-comment mo lang sa post mo kung nakuha mo ang tamang equation.
Nakuha ko na po sir. Salamat po
Paano niyo po nakuha ang sagot???
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